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METODE DEKOMPOSISI LAPLACE UNTUK MENENTUKAN SOLUSI PERSAMAAN DIFERENSIAL PARSIAL NONLINIER Sinar Ismaya; Yuni Yulida; Naimah Hijriati
EPSILON: JURNAL MATEMATIKA MURNI DAN TERAPAN Vol 10, No 1 (2016): JURNAL EPSILON VOLUME 10 NOMOR 1
Publisher : Mathematics Study Program, Faculty of Mathematics and Natural Sciences, Lambung Mangkurat

Show Abstract | Download Original | Original Source | Check in Google Scholar | Full PDF (301.029 KB) | DOI: 10.20527/epsilon.v10i1.56

Abstract

Partial differential equations are grouped into two parts: linear and nonlinear differential equations. Many natural phenomena are modeled in the form of nonlinear partial differential equations, such as K-dV and Burger equations. To be able to explain natural phenomena in the form of nonlinear partial differential equations required approach method which can then be applied to determine the solution of partial differential equation. One of the methods used to determine the solution of nonlinear differential equations is Laplace Decomposition Method which combines Laplace Transformation theory and Adomian Decomposition Method. This research is conducted by using literature method with the following procedure: Assessing Non-Linear Partial Differential Equation, Method Adomian Decomposition, Laplace Transformation and Laplace Decomposition Method; then determine the settlement of the non-linear differential equation with the Laplace Decomposition Method. The result of this research is obtained by solution of nonlinear partial differential equation of Order one by using Laplace decomposition method that is 0nnuu∞ == Σ with (????????, ????????) = ℒ-1????1????????ℒ {???????? (????????, ????????)} + 1????????ℎ (????????) ???? and ???????????????? + 1 (????????, ????????) = ℒ-1????-1????????ℒ {???????????? ???????? (????????, ????????) } -1????????ℒ {????????????????} ????; ????????≥0 and on the two-order nonlinear partial differential equation is 0nnuu = = Σ with ????????0 (????????, ????????) = ℒ-1????1????????2ℒ {???????? (????????, ????????)} + 1????????ℎ (????????) + 1????????2???????? (????????) ???? and ???????????????? + 1 (????????, ????????) = ℒ-1????-1????????2ℒ {???????????? ???????? (????????, ????????)} - 1????????2ℒ {????????????????} ????; ????????≥0